Question
How much quantity of water at 20°C is required to just melt 800gm of ice at –12°C?
The specific heat of ice is 0.5cal/gm/K.
Solution
Let m be the mass of water required to just melt the ice.
By law of calorimetry,
Heat lost by water = Heat gained by ice
Therefore,
m x l x 20 = 800 x 0.5 x 12 +800 x 80
20m = 68800
m = 3440gm
= 3.44 kg
