A faulty thermometer reads 10°C in melting ice and 140°C in boiling water at normal pressure. What will be the reading on this thermometer when true thermometer reads 40°C?

Solution

Let T be the temperature on the faulty thermometer when the true thermometer reads 40°C.
∴ $space space space straight C over 100 equals fraction numerator straight T minus 10 over denominator 140 minus 10 end fraction$

$rightwards double arrow$ $40 over 100 equals fraction numerator straight T minus 10 over denominator 130 end fraction$

$rightwards double arrow$ $space space space space space straight T equals 62$
Therefore, temperature on the faulty scale will be $space 62 degree straight C.$

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

A faulty thermometer reads 10°C in melting ice and 140°C in boiling water at normal pressure. What will be the reading on this thermometer when true thermometer reads 40°C?

Some More Questions From Mechanical Properties of Fluids Chapter

What is the condition for motion to be simple harmonic motion?

In the displacement equation y = r sin(ωt/ + ϕ) what does ϕ called and what information does it give?

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

How do you define the mean position of particle executing simple harmonic motion?

Define amplitude.

What is the net displacement of the particle executing simple harmonic motion in one complete oscillation?

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