On the stem of mercury thermometer ice point and steam point are separated by 180 mm. If the two divisions of calibration are separated by 0.5 mm then what is the least count of thermometer?

Solution

Given,
Distance between thermometer ice point and steam point = $180 space mm space equals space 100 degree straight C$
Separation between two divisions of calibrations = 0.5 mm
∴ $space space space 0.5 mm space equals space 100 over 180 cross times 0.5 space equals space left parenthesis 5 divided by 18 right parenthesis degree straight C$
i.e. least count of thermometer is $left parenthesis 5 divided by 18 right parenthesis degree straight C$

Some More Questions From Mechanical Properties of Fluids Chapter

What is the condition for motion to be simple harmonic motion?

In the displacement equation y = r sin(ωt/ + ϕ) what does ϕ called and what information does it give?

For Daily Free Study Material Join wiredfaculty

Mechanical Properties Of Fluids

On the stem of mercury thermometer ice point and steam point are separated by 180 mm. If the two divisions of calibration are separated by 0.5 mm then what is the least count of thermometer?

Some More Questions From Mechanical Properties of Fluids Chapter

What is the condition for motion to be simple harmonic motion?

In the displacement equation y = r sin(ωt/ + ϕ) what does ϕ called and what information does it give?

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

How do you define the mean position of particle executing simple harmonic motion?

Define amplitude.

What is the net displacement of the particle executing simple harmonic motion in one complete oscillation?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction