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Mechanical Properties Of Fluids

Question
CBSEENPH11019326

A simple pendulum clock is taken to a height 64 km from the surface of the earth. How much will it lose or gain in a day?

Solution

Time period of the simple pendulum is given by,  
            space space space space space space space space space space space straight T equals 2 straight pi square root of straight ell over straight g end root 
At height h, acceleration due to gravity is,
straight g subscript blank subscript h end subscript equals straight g open parentheses 1 plus straight h over straight R close parentheses to the power of negative 2 end exponent


Since h<< R, 
space space space
space space space space space therefore space space space space space straight g subscript straight h equals straight g open parentheses 1 minus fraction numerator 2 straight h over denominator straight R end fraction close parentheses 
The time period of simple pendulum clock at height h is,
space space space space space straight T subscript straight h equals 2 straight pi square root of straight ell over straight g subscript straight h end root space

space space space space space space space space equals 2 straight pi square root of fraction numerator straight ell over denominator straight g open parentheses 1 minus fraction numerator 2 straight h over denominator straight R end fraction close parentheses end fraction end root space

space space space space space space space space equals space space 2 straight pi square root of straight ell over straight g subscript straight h end root open parentheses 1 minus fraction numerator 2 straight h over denominator straight R end fraction close parentheses to the power of negative 1 divided by 2 end exponent space

space space space space space space space equals straight T open parentheses 1 plus straight h over straight R close parentheses space

rightwards double arrow space space space space space space space space straight T subscript straight h equals straight T plus straight T straight h over straight R space

rightwards double arrow space space fraction numerator straight T subscript straight h minus straight T over denominator straight T end fraction cross times 100 equals straight h over straight R cross times 100
That is, percentage increase in time period of oscillation is, 
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The time period of oscillation increases.
Therefore, the clock will lose time in a day.
Percentage increase in time period is 1%, 
therefore, it will lose 1 over 100 cross times 86400 equals 864 seconds in a day.