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Mechanical Properties Of Fluids

Question
CBSEENPH11019323
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A spring of constant 245N/m is loaded by two blocks of mass 4 kg and 5 kg. If 4 kg mass is suddenly removed, then what will be the frequency and amplitude of oscillation of 5kg mass?

Solution

We have,
Spring constant, k=245N/m
Mass, m1 = 4 kg
MAss, m2 = 5kg 
When 4 kg mass is removed from the loaded spring, the the amplitude of oscillation is equal to extension produced due to 4 kg load.
straight i. straight e. space space space straight A equals fraction numerator straight m subscript 1 straight g over denominator straight k end fraction equals fraction numerator 4 cross times 9.8 over denominator 245 end fraction equals 0.08 straight m equals 8 space cm space
The spring remains loaded by 5 kg mass. Therefore, the frequency of oscillation is, 
straight v equals fraction numerator 1 over denominator 2 straight pi end fraction square root of straight k over straight m subscript 2 end root equals fraction numerator 1 over denominator 2 straight pi end fraction square root of 245 over 5 end root equals fraction numerator 7 over denominator 2 straight pi end fraction hz 

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