-->

Mechanical Properties Of Fluids

Question
CBSEENPH11019319

A vertical U tube of uniform cross-section contains mercury up to height 39-2cm. Find the time period of oscillation when it is disturbed. Also find the time period of oscillation if mercury in the tube is replaced by water to same height.

Solution
The time period of oscillation of liquid in U tube is given by,
                       straight T equals 2 straight pi square root of straight L over straight g end root 
where,
L is the length of the mercury column in each limb of U- tube. 
We have,
Length, L = 39.2 cm
therefore space T i m e space p e r i o d comma space straight T equals 2 straight pi square root of fraction numerator 39.2 over denominator 980 end fraction end root equals 1.257 straight s
Since the time period of oscillation does not depend on the nature of liquid in U tube, therefore time period of oscillation will remain same on replacing mercury by water.