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Mechanical Properties Of Fluids

Question
CBSEENPH11019316

Two bodies P and Q of equal asses are suspended from two separate springs of constants K1 and k2 respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, then what is the ratio of the amplitudes of vibration of P and Q?

Solution
Frequency of oscillation of body P is,
                  straight omega subscript 1 equals square root of straight K subscript 1 over straight m end root 
Frequency of oscillation of body Q is,
                 straight omega subscript 1 over straight w subscript 2 equals square root of straight K subscript 2 over m end root
The ratio of the frequency of  oscillation of body P to Q is,
                  
straight omega subscript 1 over straight omega subscript 2 equals square root of straight K subscript 1 over straight K subscript 2 end root 
Let, Aand Abe the amplitude of oscillation of P and Q respectively.
Since the velocity of P and Q at mean position (maximum velocity) is equal,  therefore

space space space space space space space space space straight A subscript 1 straight omega subscript 1 equals straight A subscript 2 straight omega subscript 2 space

rightwards double arrow space space space space straight A subscript 1 over straight A subscript 2 equals straight omega subscript 2 over straight omega subscript 1 equals square root of straight K subscript 2 over straight K subscript 1 end root