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Mechanical Properties Of Fluids

Question
CBSEENPH11019223

n1 moles of gas A at temperature T1 and n2 moles of gas B at temperature T2 are mixed together without loss of energy. Find the temperature of mixture.

Solution
Gas A:

Number of moles of gas = n1 
Temperature = T1
K.E of 1 molecule of gas = 32KT1
Total K.E = n1N32KT1 

Gas B

Number of moles of gas = n2
Temperature = T2 
K.E of 1molecue = 32KT2 
Total K.E = n2 N32KT2

Now, total kinetic energy of the mixture is,

               K.E = 32kNn1T1 + n2T2   ... (1)
Let, the temperature of the mixture at equilibrium be T.  The total K.E of the mixture at equilibrium is given by, 

                K.E = (n1 + n2) N32kT        ...(2) 

Now, using equations (1) and (2), we have 

                       T = n1T1 + n2T2n1 + n2