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Mechanical Properties Of Fluids

Question
CBSEENPH11019222

Estimate the average thermal energy of a helium atom at:
(i) room temperature (27°C),
(ii) the temperature on the surface of the sun (6000°K),
(iii) the temperature of 10 million degree Kelvin

(the typical core temperature in the case of a star) k = 1.38x102–3J/K.

Solution

The average thermal energy of atom/molecule is given by ,
                   U=32kT
(i) Given, 

Room temperature = 27°C = 300 K.

Therefore the average thermal energy of He atom at room temperature is, 

             u=32×1.38×10-23×300   = 6.2×10-21J   

(ii) Given, 

Temperature at surface of the sun=6000K

Therefore the average thermal energy of He atom at temperature of the sun is, 

         u=32×1.38×10-23×6000  = 1.24 × 10-19J 

(iii)  Thermal energy at temperature "
So, the average thermal energy of the He atom is, 

       u = 32kT = 32×1.38×10-23×107   =2.1 × 10-16 J