Two particles A and B execute simple harmonic motions given by the equations y_A = 10 sin12 πt, y_B = 12 sin10 πt Which has greater velocity at mean position?

Solution

The velocity at the mean position is given by,

space space space space space space space space straight nu subscript ring operator equals straight omega therefore space space space space space space straight v subscript 0 straight A end subscript equals 10 cross times 12 straight pi equals 120 straight pi a n d space space space straight v subscript omicron B end subscript equals 12 cross times 10 straight pi equals 120 straight pi

Therefore, both the particles have same velocity at the mean position.

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