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Mechanical Properties Of Fluids

Question
CBSEENPH11019286

Two identical simple pendulums are suspended from the roof of two lifts at rest and have time period of one second. One lift starts falling freely and second lift descends with constant velocity. How does the time period of the pendulums alter?

Solution
Time period of simple pendulum is,
                      straight T equals 2 straight pi square root of straight ell over straight g end root 
The body in the lift, which falls freely, will be in the state of weightlessness.
The effective value of free  g = 0.
Therefore, time period, t = ∞.
i.e. pendulum will not oscillate.
The lift is moving with constant velocity, the value of g does not change.
Therefore, the pendulum continues to beat the seconds.