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Mechanical Properties Of Fluids

Question
CBSEENPH11019265

What is the length of second's pendulum on the surface of the moon?

Solution
The pendulum whose time period is 2 seconds is called Secon's pendulum. 
That is, time period of a pendulum is given by, 
space space space space space space space straight T equals 2 straight pi square root of straight L over straight a end root
rightwards double arrow space space straight L equals fraction numerator straight T squared over denominator 4 straight pi squared end fraction straight a space

Here space space space space space space space straight T equals 2 straight s space semicolon space space space straight a equals straight g divided by 6 
[because on the surface of the moon, a=g/6]
Length space of space the space pendulum comma space space straight L equals fraction numerator straight T squared over denominator 4 straight pi squared end fraction straight a space equals space fraction numerator left parenthesis 2 right parenthesis squared over denominator 4 straight pi squared end fraction straight g over 6
       
                                                    = 0.1655m
                                                    = 16.55cm