Question
A body executes simple harmonic motion with time period T1 under the action of force F1 and with time period T2 under the action of force F2. Find the time period of oscillation if both the forces act simultaneously on the body.
Solution
Let m be the mass of the body.
Time period of oscillation of body under the action of force F1 is T1.
Therefore,
The time period of oscillation of body under the action of force F2 is T2.
Therefore,
When both the forces act simultaneously on the body, the net force is F = F1 + F2.
Let T be the time period of oscillation.
Thus,
Time period of oscillation of body under the action of force F1 is T1.
Therefore,
The time period of oscillation of body under the action of force F2 is T2.
Therefore,
When both the forces act simultaneously on the body, the net force is F = F1 + F2.
Let T be the time period of oscillation.
Thus,
