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Mechanical Properties Of Fluids

Question
CBSEENPH11019255

Show that motion of a loaded spring is simple harmonic motion and calculate its time period of oscillation.Show that motion of a loaded spring is simple harmonic motion and calculate its time period of oscillation.

Solution
Let a point mass m be suspended from a massless spring suspended from a rigid support O.

                    
Let due to load m the spring extend by length l to acquire the equilibrium.
The restoring force set up in the spring is,
                          straight F subscript 1 equals negative straight k straight ell 
where,
k is the spring constant of the spring.
Negative sign is because restoring force is in the upward direction opposite to the direction of extension which is in downward direction.
As the mass is in equilibrium, therefore
space space space space mg space equals space straight k straight ell space space space space space space

rightwards double arrow space space space space straight k equals mg divided by straight ell
Let the mass be now pulled further by a distance y.
Now the restoring force set up in the spring is,
                   straight F subscript 2 equals negative straight k left parenthesis straight ell plus straight y right parenthesis
The net force on the mass in this position is,
straight f equals straight F subscript 2 plus mg

space space equals negative straight k left parenthesis straight ell plus straight y right parenthesis plus mg space

space space equals left parenthesis negative straight k straight ell plus mg right parenthesis minus ky

space space space equals negative ky
The acceleration produced in the mass is,
straight a equals straight f over straight m equals negative straight k over straight m straight y
Thus, the acceleration is directly proportional to displacement and directed towards mean position.
Hence, the motion is simple harmonic motion.
The time period is given by, 

space space space straight T equals 2 straight pi square root of displacement over acceleration end root space

space space space straight T equals 2 straight pi square root of fraction numerator straight y over denominator straight k divided by straight m end fraction end root space

space space space straight T equals 2 straight pi square root of straight m over straight k end root space

space space space straight T equals 2 straight pi square root of straight ell over straight g end root space space space space space space space space space space space space space space open square brackets because space mg space equals straight k straight ell close square brackets