Question
The black oxide of copper is prepared in four different ways and the following observations noted:
|
Copper (in g) |
Copper oxide (in g) |
|
5.015 |
6.284 |
|
8.286 |
10.357 |
|
18.443 |
23.169 |
|
12.011 |
15.051 |
What do you infer from this data?
Solution
Fraction of the copper present in the oxide of copper is:
(a) 5.015/6.284 = 0.798
(a) 5.015/6.284 = 0.798
(b) 8.286/10.357 = 0.800
(c) 18.443/23.169 = 0.796
(d) 12011/15.051 = 0.798
Since the fraction of the copper present in the oxide of copper is constant, this proves the law of constant proportions.
