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Mechanical Properties Of Fluids

Question
CBSEENPH11019132

Derive the differential equation of simple harmonic motion.

Solution

The acceleration of particle executing simple harmonic motion, a = – ω2y

We know that the acceleration is second derivative of displacement.
Therefore, 
 space space space space space space space space space space space space space space straight a equals fraction numerator straight d squared straight y over denominator dt squared end fraction
therefore space space space fraction numerator straight d squared straight y over denominator dt squared end fraction equals negative straight omega squared straight y
space space space space space space fraction numerator straight d squared straight y over denominator dt squared end fraction plus straight omega squared straight y equals 0 
The above equation represent the differential equation of simple harmonic motion.