Question
The position of the particle oscillating along X-axis is given by x = 4(sin100 πt) + 2. Find the extreme positions in which the particle is oscillating.
Solution
The extreme positions of the oscillating particle are the maximum and minimum value of x.
Maximum value of sin100 πt is +1 and minimum value is – 1.
Therefore,
Thus the particle oscillates between the position -2 and 6.
Maximum value of sin100 πt is +1 and minimum value is – 1.
Therefore,
Thus the particle oscillates between the position -2 and 6.
