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Mechanical Properties Of Fluids

Question
CBSEENPH11018951

Two plane sonic waves of intensity I1 and I2 (I1 > I2) are travelling in a homogeneous media. A detector moving perpendicular to right bisector of two source records the intensity varying between 20db to 27.6db. Find I1 and I2.

Solution
Loudness and intensity are related as,
straight L space equals space 10 space log space open parentheses straight I over straight I subscript straight o close parentheses dB space

where space straight I subscript straight o space equals space 10 to the power of negative 12 end exponent space straight W divided by straight m squared space

straight I space equals space straight I subscript straight o space Antilog space left parenthesis straight L over 10 right parenthesis space space space space space space... space left parenthesis 1 right parenthesis thin space

Given space that comma space

straight L subscript max space equals space 27.6 space db comma space space space space space space straight L subscript min space equals space 20 space db space

therefore space straight I subscript max space equals space straight I subscript 0 space Antilog space open parentheses fraction numerator 27.60 over denominator 10 end fraction close parentheses space equals space 576 space straight I subscript straight o space

and space straight I subscript min space equals straight I subscript straight o space Antilog space open parentheses 20 over 10 close parentheses space equals space 100 space straight I subscript straight o space

Also comma space

straight I subscript max space equals space open parentheses square root of straight I subscript 1 end root space plus space square root of straight I subscript 2 end root close parentheses squared space comma space and space

straight I subscript min space equals space space open parentheses square root of straight I subscript 1 end root space minus space square root of straight I subscript 2 end root close parentheses squared space

therefore space space open parentheses square root of straight I subscript 1 end root space plus space square root of straight I subscript 2 end root close parentheses squared space equals space 576 space straight I subscript straight o space space space space space space space space space... space left parenthesis 2 right parenthesis thin space
and
open parentheses square root of straight I subscript 1 end root space minus space square root of straight I subscript 2 end root close parentheses squared space equals space 100 space straight I subscript straight o space space space space space space space space space space space space space space space space... space left parenthesis 3 right parenthesis

Now comma space solving space left parenthesis 2 right parenthesis space and space left parenthesis 3 right parenthesis comma space we space get

straight I subscript 1 space equals space 289 space space straight I subscript straight o space equals space 289 space cross times space 10 to the power of negative 12 end exponent space straight W divided by straight m squared space

straight I subscript 2 space equals space 49 space space straight I subscript straight o space equals space 49 space cross times 10 to the power of negative 12 end exponent space straight W divided by straight m squared



space