Sponsor Area

Mechanical Properties Of Fluids

Question
CBSEENPH11018936

What is the principle of venturimeter? Derive an expression for the rate of flow of liquid through it.

Solution

Venturimeter is based on Bernoulli's theorem. It consists of a two truncated tubes connected by a pipe at narrow ends. The pipe connecting the two tubes is called throat. 

i) Venturimeter tube is positioned horizontally and the liquid is made to enter in it from end A and after passing through throat BC, it leaves tube at end D.

ii) Let at A,
Area of cross-section of tube = a1,
Pressure of liquid = P1 
Velocity = v1 
At the throat,
Area of cross-section of tube = a2 
Pressure of liquid = P2 
Velocity be v2

According to the equation of continuity, 
straight a subscript 1 straight v subscript 1 space equals space straight a subscript 2 straight v subscript 2 space space space space space space space space space space... space left parenthesis 1 right parenthesis space

According space to space Bernoulli apostrophe straight s space Theorem comma space

straight P subscript 1 over straight rho plus 1 half straight v subscript 1 squared space plus space gh subscript 1 space equals space straight P subscript 2 over straight rho plus 1 half straight v subscript 2 squared space plus space gh subscript 2 space space space... space left parenthesis 2 right parenthesis

As space the space tube space is space horizontal comma space therefore

straight h subscript 1 space equals space straight h subscript 2 space

Substituting space in space equation space left parenthesis 2 right parenthesis comma space we space get space

straight P subscript 1 over straight rho plus 1 half straight v subscript 1 squared space equals space straight P subscript 2 over straight rho plus 1 half straight v subscript 2 squared space space space space space space space space space space space space space space... space left parenthesis 3 right parenthesis

Solving space left parenthesis 1 right parenthesis space and space left parenthesis 3 right parenthesis space for space straight v subscript 1 comma space we space get

straight v subscript 1 space equals space straight a subscript 2 space square root of fraction numerator 2 left parenthesis straight P subscript 1 minus straight P subscript 2 right parenthesis over denominator straight rho space left parenthesis straight a subscript 1 squared space minus space straight a subscript 2 squared right parenthesis thin space end fraction end root space space space space space space space space space space space space space space... space left parenthesis 4 right parenthesis space

If space the space difference space in space the space height space of space the space liquid space in space
the space manometer space is space straight h comma space then space straight P subscript 1 space minus space straight P subscript 2 space equals space ρgh

Thus comma space

straight v subscript 1 space equals space straight a subscript 2 square root of fraction numerator 2 gh over denominator left parenthesis straight a subscript 1 squared space minus space straight a subscript 2 squared right parenthesis end fraction end root space space space space space space space space space space... space left parenthesis 5 right parenthesis thin space

Now comma space the space rate space of space flow space of space liquid space through space the space
venturimeter space is comma space

straight V space equals space straight a subscript 1 straight v subscript 1 space equals space straight a subscript 1 straight a subscript 2 space square root of fraction numerator 2 gh over denominator left parenthesis straight a subscript 1 squared space minus space straight a subscript 2 squared right parenthesis end fraction end root