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Mechanical Properties Of Fluids

Question
CBSEENPH11018913

A pipe 20 cm long is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 430 Hz source? Will the same source be in resonance with the pipe if both ends are open? (speed of sound = 340 m/s)

Solution

Length of one end closed pipe is, L =  20 cm = 0.20m 
Frequency of source is, v = 430 Hz 
We know that the frequency of nth mode is given by, 
            straight v space equals space left parenthesis 2 straight n minus 1 right parenthesis fraction numerator straight v over denominator 4 straight L end fraction 
Let nth mode of pipe be in resonance with the source. 
Therefore, 
              430 equals left parenthesis 2 straight n minus 1 right parenthesis fraction numerator 340 over denominator 4 cross times 0.2 end fraction 
rightwards double arrow              straight n equals 1 
Therefore, the fundamental mode of pipe is in resonance with the source.
If both the ends of pipe are open then frequency of nth mode is, 
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Substituting the values, we get 
           430 equals straight n fraction numerator 340 over denominator 2 cross times 0.2 end fraction 
rightwards double arrow          n = 0.5, which is not possible. Therefore, if both the ends are open, then pipe cannot be in resonance with the source.