Question
Capillaries of length I, 16l and 81l are connected in series. The radii of the capillaries are r, 2r and 3r respectively. If the pressure difference across smallest pipe is P, then find the total pressure difference across the series combination.
Solution
Let P1, P2 and P3 be the pressure difference across first, second and third capillary tube respectively.
Since all the three capillaries are in series.
Therefore the rate of flow of fluid through all the three capillaries will be same.
That is,
P1 = P2 = P3
Since,
P1 = P
Therefore the total pressure across serial combination is,
Since all the three capillaries are in series.
Therefore the rate of flow of fluid through all the three capillaries will be same.
That is,
P1 = P2 = P3
Since,
P1 = P
Therefore the total pressure across serial combination is,
