Question
Two wires of length 120cm and 90cm and radii 0-8mm and 0.9mm respectively are made from same material. Find the interval between their fundamental frequencies when two wires are stretched by equal forces.
Solution
The fundamental frequency of vibration of stretched string is given by their fundamental frequencies when two wires are stretched by equal forces.
That is,
The fundamental frequency of vibration of first wire is,
The fundamental frequency of vibration of second wire is,
∴![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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We have,
∴
When two wires are stretched by equal forces, the fundamental frequencies lie between 27 and 32.
That is,
The fundamental frequency of vibration of first wire is,
The fundamental frequency of vibration of second wire is,
∴
We have,
∴
When two wires are stretched by equal forces, the fundamental frequencies lie between 27 and 32.
