Question
A particle starts moving from position of rest under a constant acceleration. If it travels a distance x in t second, what distance will it travel in next t second?
Solution
Given,
Initial velocity, u = 0
Distance travelled, s = x
Time taken to travel x distance, t = t sec
Now, using the relation, 
we have
x = 0 + 1/2 at2 ... (1)
Let the body travel a distance y in next t seconds.
The total distance travelled in t+t = 2t sec will be (x+y).
Therefore,
(x+y) = 1/2 a (2t)2
= 1/2a x 4t2 ... (2)
Dividing equation (2) by (1), we have
