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Motion In A Plane

Question
CBSEENPH11018648

A plane flying horizontally at 100 m/s at a height of 1000 m releases a bomb from it. Find the time it takes to reach the ground. 

Solution

We have, 
Initial distance, yo = 0
Height attained after time t, y = 1000 m 
Initial velocity, uy = 0 m/s 
Acceleration, ay = 9.8 m/s2 
Time = t 
Now, using the equation of motion, we have 
space space space space straight y space equals space straight y subscript straight o space plus space straight u subscript straight y straight t space plus space 1 half straight a subscript straight y straight t squared space
therefore space 1000 space equals space 0 space plus space 0 space left parenthesis straight t right parenthesis space plus space 1 half cross times 9.8 cross times space straight t squared space

space space space space space space space space space space space space equals space 4.9 space straight t squared space

rightwards double arrow space straight t space equals space square root of fraction numerator 1000 over denominator 4.9 end fraction end root space equals space 100 over 7 space equals space 14.28 space sec
Therefore, 14.28 sec ia taken for the bomb to reach the ground.