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Motion In A Plane

Question
CBSEENPH11018642

A cyclist starts from the centre O of a circular track of radius 1 km, reaches the edge A of the track and then cycles along the circumference and stops at point B. If the total time taken is 10 minutes, what is the a) average velocity b) average speed of the cyclist. 

Solution

a) Displacement in 10 min (=1/6 hr) = OB = r = 1 km
Therefore, 
Average velocity = fraction numerator 1 space km over denominator 1 divided by 6 space straight h end fraction space equals space 6 space k m divided by h r
b) Distance travelled in 1/6 hr = 0 to A (along radius)  + A to B (along the arc)
                                              = r + rπ over 3
                                              = 1 km + 1 km + fraction numerator 22 over denominator 7 space straight x space 3 end fraction
                                               = 2.05 km
Therefore, 
Averge speed = fraction numerator 2.05 over denominator left parenthesis 1 divided by 6 right parenthesis straight h space end fraction = 12.30 km/hr