Question
A body is projected from the ground with some velocity. Three seconds later the body is moving in a direction making an angle of 30° with the horizontal and two seconds later it moves horizontally. Find the distance at which the body will fall on the ground from the point of projection.
Solution
Let the body be projected with velocity u making an angle θ with the horizontal.
The direction of motion of body after t seconds of throw is given by the equation,
Here at time, t = 3 the value of is
and at t = 5s the value of
is
∴ ...(1)
and
...(2)
From (2),
...(3)
Substituting in equation (1), we get
...(4)
The horizontal range of the body,
Therefore, the body falls at a distance of 200 from the point of projection.