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Motion In A Plane

Question
CBSEENPH11018593

A stone is thrown from the top of a tower 50m high with speed 30m/s at an angle 30° with horizontal. Find the distance from the foot of tower where the stone will hit the ground.

Solution

Given that, 

      u = 30 m/s,       straight theta equals 30 degree
∴ x component of velocity, 
straight u subscript straight x equals 30 space cos space 30 degree space equals space 25.98 space straight m divided by straight s
and  
y component of velocity,   
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Let the stone reaches the ground after time t.
                space space space space space space space straight y equals straight y subscript straight o plus straight u subscript straight y straight t plus 1 half straight a subscript straight y straight t squared      ... (1)

We have,
       straight y equals 0 comma space space straight y subscript straight o equals 50 comma space space space straight a subscript straight y equals negative 10 straight m divided by straight s squared
Putting the values in equatuion (1), we have 
           0 equals 50 plus 15 straight t minus 5 straight t squared
i.e.,            straight t equals 5 straight s
The distance from the foot of tower where the stone will hit the ground is,
              s = u x t
                 = 25.98 x 5
                 = 104.9m