Question
A stone is thrown from the top of a tower 50m high with speed 30m/s at an angle 30° with horizontal. Find the distance from the foot of tower where the stone will hit the ground.
Solution
Given that,
u = 30 m/s,
∴ x component of velocity,
and
y component of velocity,
Let the stone reaches the ground after time t.
... (1)
We have,
Putting the values in equatuion (1), we have
i.e.,
The distance from the foot of tower where the stone will hit the ground is,
s = u x t
= 25.98 x 5
= 104.9m