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Motion In A Plane

Question
CBSEENPH11018584

A bullet fired from a gun with a velocity of 800 ft/s strikes the ground at the same level as the gun at a distance of 17320 ft. Find the angle of inclination with the horizontal at which the gun was fired.

Solution

Given that,
Distance of the gun, R = 17320 ft
Initial velocity, u = 800 ft./sec
Horizontal range is given by,
                   straight R equals fraction numerator straight u squared space sin space 2 straight theta over denominator straight g end fraction
Therefore,
sin space 2 straight theta space equals space Rg over straight u squared

space space space space space space space space space space space space equals space fraction numerator 17320 space cross times space 2 over denominator left parenthesis 800 right parenthesis squared end fraction

space space space space space space space space space space space space equals space 0.866
rightwards double arrow2 straight theta space equals space 60 degree
rightwards double arrow  straight theta space equals space 30 degree, is the angle of inclination with the horizontal at which the gun was fired.