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Motion In A Plane

Question
CBSEENPH11018581

A body is projected with velocity u at angle θ with vertical. At what height will it strike the wall, r distance away from the point of projection?

Solution
Consider a body which is projected from O in XY plane with velocity 'u' at angle θ with vertical, and
The body is projected at an angle α = 90°–θ with the horizontal. 
Let the body strike the wall at height h.
So, co-ordinates of point P where the projectile hits the wall are ↔ (r,h).
Equation of trajectory is given by, 
space space space space straight y equals xtanα minus 1 half straight g fraction numerator straight x squared over denominator straight u squared cos squared straight alpha end fraction 
     equals xcotθ minus 1 half straight g. fraction numerator straight x squared over denominator straight u squared sin squared straight theta end fraction        [∵ straight alpha equals 90 degree minus straight theta
Since straight P left right arrow left parenthesis straight r comma space straight h right parenthesis lies on trajectory, 
∴        straight h equals rcotθ minus 1 half straight g fraction numerator straight r squared over denominator straight u squared sin squared straight theta end fraction
is the height at which the body will strike the wall.