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Motion In A Plane

Question
CBSEENPH11018579

A body of mass 2 kg is projected with a velocity 60 m/sec at an angle of 30°. What is the height of the body from ground at t = 2·5s? (Take g = 10 m/s2)

Solution
The height of the body from ground at any instant is given by,
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#6 {main}</pre>         ... (1)
Given that,
Mass of the body, m = 2 kg
Initial space velocity space of space the space body comma space straight u equals 60 space straight m divided by straight s

Angle space of space projection comma space straight theta space equals space 30 degree
Time, t = 2.5s
Acceleration due to gravity,straight g equals 10 space straight m divided by straight s squared
Putting this in equation (1), we will get the height of the body from the ground,
 space space space space straight h equals 60 space sin 30 degree cross times 2.5 minus 1 half cross times 10 cross times left parenthesis 2.5 right parenthesis squared
      equals 75 minus 31.25

equals space 43.75 straight m