-->

Motion In A Plane

Question
CBSEENPH11018575

Show that the ratio of the horizontal range to the maximum height attained by projectile is equal to 4 cot straight theta and is independent of speed of projection.

Solution
The horizontal range attained by projectile projected with velocity u at angle θ is, 
                   straight R equals fraction numerator straight u squared sin 2 straight theta over denominator straight g end fraction 
Maximum height attained by projectile projected with velocity u at angle θ is, 
                     straight H equals fraction numerator straight u squared sin squared straight theta over denominator 2 straight g end fraction
The ratio of horizontal range to maximum height is given by, 
    straight R over straight H equals fraction numerator straight u squared sin space 2 straight theta over denominator straight g end fraction cross times fraction numerator 2 straight g over denominator straight u squared sin squared straight theta end fraction equals 4 space cotθ

Hence, the result proved.