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Motion In A Plane

Question
CBSEENPH11018563

A body is projected with velocity u at an angle θ and reaches the ground at time T. What will be the time of flight if the body is projected with same speed at an angle (90°–θ)?

Solution
Time of flight for angle of projection straight theta is given by,
 
         straight T equals fraction numerator 2 straight u space sin space straight theta over denominator straight g end fraction                                     ...(1)
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#6 {main}</pre>, then the time of flight T' is
      straight T apostrophe equals fraction numerator 2 straight u space sin left parenthesis 90 degree minus straight theta right parenthesis over denominator straight g end fraction equals fraction numerator 2 straight u space cosθ over denominator straight g end fraction          ...(2)
Dividing (2) by (1), we get
          straight T apostrophe space equals space straight T space cot space straight theta