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Motion In A Plane

Question
CBSEENPH11018545

A projectile is projected horizontally with velocity u and allowed to fall only under gravity. Discuss the trajectory of projectile. 

Solution
Consider a projectile, which is projected with velocity 'u' in horizontal direction from a point at height h from the ground. 
Let origin be the point of projection. 
The right direction is positive direction of X-axis and vertically downward direction is positive direction of Y-axis.
The component of velocity and acceleration is resolved into horizontal and vertical components.
So, 
                    straight x subscript straight o equals 0 space space space space space space space space space space space space space space space space space space space straight y subscript straight o equals 0
straight u subscript straight x space equals straight u space space space space space space space space space space space space space space space space space space straight u subscript straight y space equals space 0
straight a subscript straight x space equals space 0 space space space space space space space space space space space space space space space space space straight a subscript straight y space equals space straight g 
Motion along horizontal direction is, 
     space space space space space space space space space straight x equals straight x subscript straight o plus straight u subscript straight x straight t plus 1 half straight a subscript straight x straight t squared equals ut              ...(1) 
Motion along vertical direction is,
            straight y equals straight y subscript straight o plus straight u subscript straight y straight t plus 1 half straight a subscript straight y straight t squared equals 1 half gt squared         ...(2)
Eliminating 't' from (1) and (2), we get
                        straight y equals open parentheses fraction numerator straight g over denominator 2 straight u squared end fraction close parentheses straight x squared 
This is the required equation of trajectory.
Since the equation of trajectory is an equation of parabola, therefore path of projectile is parabola.