Question
A particle has the following displacements in succession i) 12 m towards east ii) 5 m towards north and iii) 6 m vertically. Find the magnitude of the resultant displacement?
Solution
Here, we have
x = 12 m ; y = 5 m ; z = 6m
Then, resultant vector is given by,
r = (x2 + y2 + z2 ) 1/2
= ( 122 + 52 + 62)1/2
= (205)1/2
= 14.31 m
