-->

Motion In A Plane

Question
CBSEENPH11018492

A river 100 m wide is running downwards at the rate of 1 km per hour and a swimmer who can swim at the rate of 3·6 km/hr wishes to reach a point just opposite. Along which direction should he strike and how long will he take to cross the river?

Solution
Given, 
Width of the river = 100 m 
Rate of flow of river = 1 km/hr
Rate of flow of swimmer = 3.6 km/hr

Let the swimmer dive at an angle straight theta as shown in figure to reach the point B directly opposite to A. 
From the fig., we have
∴     straight v subscript straight m sinθ space equals space straight v subscript straight r 
rightwards double arrow      sinθ space equals space straight v subscript straight r over straight v subscript straight m equals fraction numerator 1 over denominator 3.6 end fraction equals 0.278 
rightwards double arrow           straight theta equals 16.14 degree 
Therefore, the swimmer should dive at angle (90 + 16·14) =106·14° with the direction of flow.
Now,
Time taken to cross the river, t = fraction numerator AB over denominator straight v subscript straight m cosθ end fraction
                                              equals fraction numerator 0.1 over denominator 36 cross times 16.14 end fraction
                                              equals 0.0289 space hr
equals space 104.1 space straight s