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Motion In A Plane

Question
CBSEENPH11018489

A river d km wide is flowing at the rate straight v subscript 1 straight m divided by straight s. A swimmer which can swim with velocity straight v subscript 2 relative to water wants to cross the river straight across. Find how long will he take to cross the river?

Solution
The path AB is the shortest path to cross the river.
To cross the river straight across along path AB, the resultant velocity of swimmer and the water flow should be along AB i.e. perpendicular to the direction of water flow.
           
To meet this condition, let the swimmer start swimming upstream at angle 0 with AB.
Therefore,
tan 90 degree space equals space fraction numerator straight v subscript 2 sin left parenthesis 90 degree plus straight theta right parenthesis over denominator straight v subscript 1 plus straight v subscript 2 cos left parenthesis 90 degree plus straight theta right parenthesis end fraction

rightwards double arrow space space space space space space space straight v subscript 1 plus straight v subscript 2 space cos left parenthesis 90 degree plus straight theta right parenthesis space equals space 0

rightwards double arrow space space space space space space space space space space space space space space space space space space space space space straight v subscript 1 minus straight v subscript 2 space sinθ space equals space 0
rightwards double arrow space space space space space space space space space space space space space space space space space space sinθ space equals space straight v subscript 1 over straight v subscript 2 
Now,
 
         straight v equals straight v subscript 2 space cosθ space equals space straight v subscript 2 square root of 1 minus sin squared straight theta end root

space space equals space straight v subscript 2 square root of 1 minus straight v subscript 1 squared over straight v subscript 2 squared end root space equals space square root of straight v subscript 2 squared minus straight v subscript 1 squared end root 
Time taken by the swimmer to cross the river is,
        space space space space space space space space space straight t equals straight d over straight v equals fraction numerator straight d over denominator square root of straight v subscript 2 squared minus straight v subscript 1 squared end root end fraction