Question
A stone of mass 10 kg is placed on the horizontal floor and it is pulled by a force F acting at angle 45°. What is tension in the string when it breaks off from the ground? (g = 10m/s2).
Solution
Given,
Mass of the stone, m = 10kg
Angle at which the force is acting = 45o

When vertical component of the applied force is equal to the weight of stone, the stone will lose contact.
i.e., F sin45o = 100

Therefore tension in string is
Mass of the stone, m = 10kg
Angle at which the force is acting = 45o

When vertical component of the applied force is equal to the weight of stone, the stone will lose contact.
i.e., F sin45o = 100

Therefore tension in string is
