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Mechanical Properties Of Fluids

Question
CBSEENPH11018315

Derive an expression for excess of pressure inside a soap bubble.

Solution

Consider a soap bubble of radius R and surface tension T.
There are two free surfaces of soap bubble. Due to surface tension the molecules on the surface film experience the net force in inward direction normal to the surface.
Therefore there is more pressure inside than outside.
Let pi be pressure inside the liquid drop and po the pressure outside the drop.
Therefore excess of pressure inside the liquid drop is,

                     p =p1–Po


Due to excess of pressure inside the liquid drop, the free surface of the drop will experience the net force in outward direction due to which the drop expands.
Let the free surface be displaced by dR under isothermal conditions.

Therefore excess of pressure does the work in displacing the surface and that work will be stored in the form of potential energy.

The work done by excess of pressure in displacing the surface is,
dW= Force x displacement 
     = (excess of pressure x Surface area) x displacement of surface
    italic equals p italic cross times italic 4 pi R to the power of italic 2 cross times dR space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis 
Increase in the potential energy is given by, 
dU = surface tension x increase in area of the free surface
    
equals space straight T space open square brackets 2 open parentheses 4 straight pi open parentheses straight R plus dR squared close parentheses minus 4 πR squared close parentheses close square brackets
equals space straight T space open square brackets 2 open curly brackets 4 straight pi open parentheses 2 RdR close parentheses close curly brackets close square brackets space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis
From (1) and (2)
   straight p cross times 4 πR squared cross times dR equals space straight T left square bracket space 2 space left curly bracket 4 straight pi left parenthesis 2 RdR space right parenthesis space right curly bracket space right square bracket
rightwards double arrow space space space space space space space space space space space space space space space space straight p space equals space fraction numerator 4 straight T over denominator straight R end fraction
p is the excess of pressure inside a soap bubble.