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Mechanical Properties Of Fluids

Question
CBSEENPH11018380

If an air bubble of 5.0 mm is formed at depth of 40.0 cm inside a container containing soap solution (of relative density 1.20), what would be the pressure inside the bubble?(1AP = 1.013 x105 Pa and surface tension of soap solution is 0-025 N/m)

Solution
Total pressure inside the air bubble in the soap solution is the sum of the atmospheric pressure, pressure due to height column of soap solution and excess of pressure due to surface tension.
That is,
                  
straight P equals 1 Ap plus ρgh plus fraction numerator 2 straight T over denominator straight r end fraction 
The relative density of soap solution is 1.2.
Therefore,
Relative density, straight rho=1.2 gm/cc = 1200 kg/m
Therefore comma space

Pressure comma space ρgh equals 1200 cross times 9.8 cross times 0.4

space space space space space space space space space space space space space space space space space space space space space space space space space space equals 4.7 cross times 10 cubed Pa equals 0.047 cross times 10 to the power of 5 space Pa

and space space space space fraction numerator 2 straight T over denominator straight r end fraction equals fraction numerator 2 cross times 2.5 cross times 10 to the power of negative 2 end exponent over denominator 5 cross times 10 to the power of negative 3 end exponent end fraction equals 10 Pa

Thus comma

Pressure space inside space the space bubble space is comma space

straight P subscript inside space equals 1.01 cross times 10 to the power of 5 plus 0.047 cross times 10 to the power of 5 plus 10

space space space space space space space space space space space space equals 1.05701 cross times 10 to the power of 5 Pa