The excess of pressure inside the bubble of radius 2-4 cm is balanced by 0-12 cm height column of oil of density 0.8 gm/cc. Find the surface tension of liquid.

Solution

Given, the excess of pressure inside the bubble is, height column of oil of density 0.8 gm/cc.

Find: surface tension of liquid?

The formula for excess pressure is given by,

Δp = \frac{4 T}{r}

The pressure at height column of oil is given by,

Pm = pgh

Now, excess of pressure inside the bubble is balanced by height column of oil.

Therefore,

\frac{4 T}{r} = ρgh \Rightarrow T = \frac{ρrgh}{4} Here r = 2.4 cm, ρ = 0.8 gm / cc h = 0.12 cnm, g = 980 cm / s^{2} ∴ S u r f a c e t e n s i o n o f t h e l i q u i d, T = \frac{0.8 \times 2.4 \times 980 \times 0.12}{4} = 56.45 dyne / cm

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

The excess of pressure inside the bubble of radius 2-4 cm is balanced by 0-12 cm height column of oil of density 0.8 gm/cc. Find the surface tension of liquid.

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