Find the excess of pressure inside the soap bubble of diameter 1.2mm. The surface tension of soap solution is 18 dyne/cm.

Solution

Given,
Diameter of the soap bubble, d = 1.2 mm

Surface tension of soap, T = 18 dyne/cm

So, excess of pressure inside the soap bubble is given by,

Δp = \frac{4 T}{r} Here, T = 18 dyne / cm D = 1.2 mm = 0.12 cm ∴ E x c e s s p r e s s u r e, ∆ p = \frac{4 x 18}{0.06} = 1.2 \times 10^{3} dyne / {cm}^{2} = 1.2 \times 10^{2} N / m^{2}

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