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Motion In A Plane

Question
CBSEENPH11018360

Show that straight A with rightwards arrow on top cross times straight B with rightwards arrow on top is perpendicular to <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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Solution

The dot product of two perpendiculars vectors is zero.
Therefore, to prove straight A with rightwards arrow on top cross times straight B with rightwards arrow on top to be perpendicular to space straight A with rightwards arrow on top comma we have to prove space space space space left parenthesis straight A with rightwards arrow on top cross times straight B with rightwards arrow on top right parenthesis space times space straight A with rightwards arrow on top 
So, 
left parenthesis straight A with rightwards harpoon with barb upwards on top space cross times space straight B with rightwards harpoon with barb upwards on top right parenthesis. space straight A with rightwards harpoon with barb upwards on top space equals space open parentheses straight A with rightwards harpoon with barb upwards on top space cross times stack space straight A with rightwards harpoon with barb upwards on top close parentheses. space straight B with rightwards arrow on top space equals space 0 space. space straight B with rightwards harpoon with barb upwards on top space equals space 0

straight i. straight e. comma space open parentheses straight A with rightwards harpoon with barb upwards on top cross times straight B with rightwards harpoon with barb upwards on top close parentheses space perpendicular space straight A with rightwards harpoon with barb upwards on top 
Hence, the result.