Question
Wooden plank weighing 8kg floats in water with two-fifth of its volume floating in water. Find the maximum weight that can be placed over the plank so that it may float completely submerged.
Solution
Let V be the volume of the plank.
Given that two-fifth volume of plank is submerged in water.
Therefore by law of floatation the weight of wooden plank is equal to the weight of![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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volume of water.
That is,
Weight of
of water = 8 kg
Weight of V volume of water=20kg.
Therefore when wooden plank is fully submerged in water, it displaces 20 kg of water.
Hence a 20 kg weight can be made to float over the water.
Thus additional weight that can be put over the plank is (20 – 8)kg = 12 kg.
Given that two-fifth volume of plank is submerged in water.
Therefore by law of floatation the weight of wooden plank is equal to the weight of
volume of water.That is,
Weight of
of water = 8 kgWeight of V volume of water=20kg.
Therefore when wooden plank is fully submerged in water, it displaces 20 kg of water.
Hence a 20 kg weight can be made to float over the water.
Thus additional weight that can be put over the plank is (20 – 8)kg = 12 kg.
