Discuss how we measure the volume of an irregular body using Archimedes’ principle.

Solution

According to Archimedes principle, in order to measure the volume of a body, weigh it in air and in liquid.

Let,
W₁ and W₂ be the weight of body in air and liquid,
V be the volume of body, and
ρ be the density of liquid.

Now, as per Archimedes’s principle, decrease in weight of body in liquid is equal to the weight of liquid displaced by body.

That is,

V ρ g = W_{1} - W_{2} \Rightarrow V = \frac{W_{1} - W_{2}}{ρg}

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

Discuss how we measure the volume of an irregular body using Archimedes’ principle.

Some More Questions From Mechanical Properties of Fluids Chapter

Which phase of fluid is more compressible?

What is an ideal liquid?

Do liquids exert pressure?

Define pressure.

What is the direction of pressure?

What is the direction in which pressure exerts force on the walls of a container?

What is the SI unit of pressure?

You have two identical glass flasks. One is open mouthed and other is filled with helium and sealed. Which of the two will weigh more?

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