A wire suspended vertically from a rigid support is loaded by 200 N weight. The load stretches the wire by 0.8mm. Find the elastic potential energy stored in the wire.

Solution

Given,
Weight of the load = 200 N
Elongation caused in the wire is given by, $∆ l = 0.8 mm = 8 \times 10^{- 4} m$

To find - Elastic potential energy stored in the wire = ?

Therefore, energy stored in the wire is given by,

$U = \frac{1}{2} F \times Δ l = \frac{1}{2} \times 200 \times 8 \times 10^{- 4} = 0.08 J$

Some More Questions From Mechanical Properties of Fluids Chapter

Which state of matter possesses rigidity?

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Mechanical Properties Of Fluids

A wire suspended vertically from a rigid support is loaded by 200 N weight. The load stretches the wire by 0.8mm. Find the elastic potential energy stored in the wire.

Some More Questions From Mechanical Properties of Fluids Chapter

Which state of matter possesses rigidity?

What is elasticity?

Name the property of material that opposes the deformation in it.

Name the quantity which has neither unit nor dimensions.

Why strain is dimensionless?

What is stress?

Name the two types of stress.

What is tensile stress?

What is compression stress?

Define tangential stress.

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