Question
When a wire is loaded by weight M1, its length is L1 and when loaded by weight M2 its length becomes L2. Find the original length of the wire.
Solution
L1 wire is loaded by weight M1 and when M2 is loaded length becomes M2.
Let L be the original length, A be the area of cross section of wire and Y be Young's modulus of the material of wire.
Therefore, the extension in wire is (L1–L) when loaded by weight M1 and that is (L2 – L) when loaded by weight M2.
Thus, Young's modulus is,
Let L be the original length, A be the area of cross section of wire and Y be Young's modulus of the material of wire.
Therefore, the extension in wire is (L1–L) when loaded by weight M1 and that is (L2 – L) when loaded by weight M2.
Thus, Young's modulus is,
