Question
A force of 2x102 N is applied on one of the piston of area of cross section 100cm2of hydraulic lift to support a car placed on the second piston of lift of area of cross section 1960cm2. Find the mass of the car.
Solution
Given,
Force, F = 2102 N
Area of cross-section of the first piston = 100 cm2
Area of cross-section of the second piston = 1960 cm2
Weight of the car = ?
Let, M be the mass of car.
The pressure on the piston on which force is applied is,
...(1)
The pressure on the second piston on which car is placed is,
...(2)
Now, According to Pascal law we have
P1 = P2
we get from equation (1) and (2),
Mass of the car, M=400 kg
Force, F = 2102 N
Area of cross-section of the first piston = 100 cm2
Area of cross-section of the second piston = 1960 cm2
Weight of the car = ?
Let, M be the mass of car.
The pressure on the piston on which force is applied is,
...(1)
The pressure on the second piston on which car is placed is,
...(2)
Now, According to Pascal law we have
P1 = P2
we get from equation (1) and (2),
Mass of the car, M=400 kg
