A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?

Solution

Given,
Weight of the girl = 50 kg = 490 N
Circular diameter of the heel = 1.0 cm = 10^-2 m

Area of the heel is given by,

$A = \frac{1}{4} {πD}^{2} = \frac{1}{4} π \times 10^{- 4} m^{2}$

Threfore, the pressure exerted by the heel on the ground is given by,

$P = \frac{W}{A} = \frac{490}{\frac{1}{4} π \times 10^{- 4}} = 6.2 \times 10^{6} N / m^{2}$

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

A 50 kg girl wearing high heel shoes balances on a single heel. The heel is circular with a diameter 1.0 cm. What is the pressure exerted by the heel on the horizontal floor?

Some More Questions From Mechanical Properties of Fluids Chapter

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What is an ideal liquid?

Do liquids exert pressure?

Define pressure.

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