Find the ratio of breaking force required to break the wire of radius r to that of 2r.

Solution

Radius of the wire is given by r and 2r.
The breaking force of wire is given by,

F = σA

where,
σ is the breaking stress (constant of material) and A is the area of cross section.

Let F₁ and F₂ be the breaking force for wires respectively.

$∴ F_{1} = {σπr}^{2} and F_{2} = σπ (2 r)^{2}$

Therefore,
$F_{2} = 4 F_{1}$

Hence the breaking force required to break the thick wire is four times the thin wire.

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

Find the ratio of breaking force required to break the wire of radius r to that of 2r.

Some More Questions From Mechanical Properties of Fluids Chapter

What is elasticity?

Name the property of material that opposes the deformation in it.

Name the quantity which has neither unit nor dimensions.

Why strain is dimensionless?

What is stress?

Name the two types of stress.

What is tensile stress?

What is compression stress?

Define tangential stress.

What type of stress is set up in the body when the deforming force produces longitudinal strain or volumetric strain?

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