Two wires of same material but different diameters d₁ and d₂ (d₁ > d₂) are loaded. Which can support more weight?

Solution

Breaking stress is defined as breaking load per unit area. Breaking stress is constant of a material.

Therefore,

Breaking load = Breaking stress X Area

= Breaking stress x \frac{{πd}^{2}}{4}

Breaking load is directly proportional to the diameter. Therefore, thick wire can support more weight than the thin wire.

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